(x+2)^2+13(x+2)+40=0

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Solution for (x+2)^2+13(x+2)+40=0 equation: 



(x+2)^2+13(x+2)+40=0

We multiply parentheses

(x+2)^2+13x+26+40=0

We add all the numbers together, and all the variables

13x+(x+2)^2+66=0

We move all terms containing x to the left, all other terms to the right

13x+(x+2)^2=-66

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